How exactly do you mean it doesn't work? Copied from my GUI:
> x = zoo(1:5, as.Date('2001-01-01')+1:5)
> x[as.Date('2001-01-05')]
2001-01-05
4
> x[as.Date('2001-01-05')] = 0
> x
2001-01-02 2001-01-03 2001-01-04 2001-01-05 2001-01-06
1 2 3 0 5
(Those actually line up correctly on my machine..)
Michael Weylandt
On Mon, Aug 29, 2011 at 2:45 PM, Gene Leynes <gleyne...@gmail.com> wrote:
> Why doesn't this work?
>
> x = zoo(1:5, as.Date('2001-01-01')+1:5)
> x[as.Date('2001-01-05')]
> x[as.Date('2001-01-05')] = 0
> x
>
>
> I think this is especially bad because it doesn't cause an error. It lets
> you do something to x, but then you can't see x again to see what it did.
>
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>
> ______________________________________________
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> http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>
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