another approach is:

Df <- as.data.frame(cbind(rcauchy(100), matrix(runif(100*50), ncol = 50)))
fit <- lm(V1 ~ ., data = Df)
fit


I hope it helps.

Best,
Dimitris


On 8/17/2011 3:28 PM, R. Michael Weylandt wrote:
The most elegant solution is going to depend on where you data comes from,
but one way to do it if you have a matrix of data:

D = cbind(rcauchy(100), matrix(runif(100*50),ncol=50)) # Some nonsense data
lm(D[,1] ~ D[,-1])

If you let us know how your data is set up, a more specific response can be
given.

Hope this helps,

Michael Weylandt

On Wed, Aug 17, 2011 at 9:23 AM, carol white<wht_...@yahoo.com>  wrote:

Hello,
It might be an easy question but if you have many variables to fit in the
lm function, how do you take all without specifying var1+var2+...+var2100 in
the terms parameter in response ~ terms?

Cheers,

Carol

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Dimitris Rizopoulos
Assistant Professor
Department of Biostatistics
Erasmus University Medical Center

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