Here's an attempt using sapply:
> x <- c(2, 2, 3, 3, 4, 6)
> ys <- 1:8
> sapply(ys, function(y) { length(which(x==y)) } )
[1] 0 2 2 1 0 1 0 0
Jeff
On Sun, Jul 31, 2011 at 2:41 PM, Paul Menzel
<paulepan...@users.sourceforge.net> wrote:
> Dear R folks,
>
>
> I am sorry to ask this simple question, but my search for the right
> way/command was unsuccessful.
>
> I have a vector
>
>> x <- c(2, 2, 3, 3, 4, 6)
>
> Now the values of x should be considered the index of another vector
> with possible greater length, say 8, and the value should be how often
> the indexes appeared in the original vector x.
>
>> length(result)
> [1] 8
>> result
> [1] 0 2 2 1 0 1 0 0
>
>
> Thank you in advance,
>
> Paul
>
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> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
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>
>
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