On Jul 28, 2011, at 9:37 AM, Maciej Hoffman-Wecker wrote:
Dear help list, I have a timestamp in as a chron object:
It would have been courteous to put in: library(chron)
(x <- chron(dates = c("12/02/11", "22/11/11"),+ times = c("07:30:00", "04:00:00"), + format = c(dates = "d/m/y", times = "h:m:s"))) [1] (12/02/11 07:30:00) (22/11/11 04:00:00) Now I want to shift the timestamp by 06:30 (hh:mm) backwards, to get [1] (12/02/11 01:30:00) (21/11/11 21:30:00)
(Your time subtraction is a bit different than R's ... or mine) > x - 6.5/24 [1] (12/02/11 01:00:00) (21/11/11 21:30:00) chron times are represented as days, so 6 1/2 hours is 6.5/24
How can I achieve this? Are there any more detailed examples on manipulation of chron objects? I have some trouble with this.
The help page has quite a few examples. I didn't know the answer but after reading the help page it was pretty easy to figure out.
David Winsemius, MD West Hartford, CT ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
