On Wed, 2011-07-27 at 01:06 -0700, steven mosher wrote:
> there are really two related problems here
>
> I have a 2D matrix
>
>
> A <- matrix(1:100,nrow=20,ncol =5)
>
>
> S <- matrix(1:10,nrow=2,ncol =5)
>
>
> #I want to subtract S from A. so that S would be subtracted from the
> first 2 rows of
>
> #A, then the next two rows and so on.
For this one, I have used the following trick to replication a matrix
do.call(rbind, rep(list(mat), N)
where we convert the matrix, `mat`, to a list and repeat that list `N`
times, and arrange for the resulting list to be rbind-ed. For your
example matrices, the following does what you want:
A - do.call(rbind, rep(list(S), nrow(A)/nrow(S)))
Whether this is useful will depend on the dimension of A and S - from
your posts on R-Bloggers, I can well imagine you are dealing with large
matrices.
> #I have a the same problem with a 3D array
>
> # where I want to subtract Q for every layer (1-10) in Z
>
> # I thought I solved this one with array(mapply("-",Z,Q),dim=dim(Z))
>
> # but got the wrong answers
>
>
> Z <- array(1:100,dim=c(2,5,10))
>
> Q <- matrix(1:10,nrow=2,ncol =5)
For this one, consider the often overlooked function `sweep()`:
sweep(Z, c(1,2), Q, "-")
does what you wanted. c(1,2) is the `MARGIN` argument over the
dimensions that Q will be swept from.
HTH
G
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Dr. Gavin Simpson [t] +44 (0)20 7679 0522
ECRC, UCL Geography, [f] +44 (0)20 7679 0565
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