Never mind - found it: x<-data.frame(a=1:10) x$b<-rep(1:3,nrow(x)%/%3,len=nrow(x))
Dimitri On Wed, Jul 20, 2011 at 6:15 PM, Dimitri Liakhovitski <dimitri.liakhovit...@gmail.com> wrote: > Apologies, for a very simple question. I forgot how to do it - > although I remember reading about getting a warning in such a > situation. > > I have a data frame. It happens to be 10 rows but it could be 11 or 3 or 13... > x<-data.frame(a=1:10) > I need to add variable "b" that is a sequence of 1:3 - repeated again > and again so that the result is: > x > a b > 1 1 > 2 2 > 3 3 > 4 1 > 5 2 > 6 3 > 7 1 > 8 2 > 9 3 > 10 1 > > > Thanks a lot! > -- > Dimitri Liakhovitski > marketfusionanalytics.com > -- Dimitri Liakhovitski marketfusionanalytics.com ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
