Hi Dimitris and everyone
I tried this but now I know why it didn't work out for me initially.
> t1=matrix(1:10,5,2)
> t2=matrix(1,5,1)
> t2
[,1]
[1,] 1
[2,] 1
[3,] 1
[4,] 1
[5,] 1
> t1
[,1] [,2]
[1,] 1 6
[2,] 2 7
[3,] 3 8
[4,] 4 9
[5,] 5 10
> t1-as.vector(t2)
[,1] [,2]
[1,] 0 5
[2,] 1 6
[3,] 2 7
[4,] 3 8
[5,] 4 9
> t1-t2
Error in t1 - t2 : non-conformable arrays
I'm too used to Matlab I guess.
Cheers,
Bo
> Date: Sun, 2 Mar 2008 18:56:15 +0100
> From: [EMAIL PROTECTED]
> To: [EMAIL PROTECTED]
> CC: r-help@r-project.org
> Subject: Re: [R] elegant way to minus on each row of a matrix
>
> try this:
>
> mat <- matrix(1:9, 3, 3, TRUE)
> dat <- as.data.frame(mat)
> vec <- 1:3
>
> result.mat <- mat - vec
> result.dat <- dat - vec
> result.mat
> result.dat
>
>
> I hope it helps.
>
> Best,
> Dimitris
>
> ----
> Dimitris Rizopoulos
> Biostatistical Centre
> School of Public Health
> Catholic University of Leuven
>
> Address: Kapucijnenvoer 35, Leuven, Belgium
> Tel: +32/(0)16/336899
> Fax: +32/(0)16/337015
> Web: http://med.kuleuven.be/biostat/
> http://www.student.kuleuven.be/~m0390867/dimitris.htm
>
>
> Quoting Bo Zhou <[EMAIL PROTECTED]>:
>
> >
> > How to do this in an elegant way formatrix/data frame/zoo?
> >
> > mat=
> > 1 2 3
> > 4 5 6
> > 7 8 9
> >
> > vector=
> > 1
> > 2
> > 3
> >
> >
> > result=
> > 0 1 2
> > 2 3 4
> > 4 5 6
> >
> > ie
> > 1-1 2-1 3-1
> > 4-2 5-2 6-2
> > 7-3 8-3 9-3
> >
> > Thanks in advance.
> >
> > _________________________________________________________________
> >
> >
> > 08
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> >
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08
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