yet another solution is:
v <- c(1, 2, 6, 5)
w <- matrix(c(1, 4, 3, 5, 8, 10), ncol = 2, byrow = TRUE)
check <- outer(w[, 1], v, "-") * outer(w[, 2], v, "-")
v[which(check <= 0, arr.ind = TRUE)[, 2]]
Best,
Dimitris
On 6/24/2011 10:05 PM, Martin Morgan wrote:
On 06/24/2011 11:12 AM, Dennis Murphy wrote:
Hi:
Not much different from Peter's approach, but here's another try:
v<- c(1, 2, 6, 5)
w<- matrix(c(1, 4, 3, 5, 8, 10), ncol = 2, byrow = TRUE)
w
[,1] [,2]
[1,] 1 4
[2,] 3 5
[3,] 8 10
f<- function(x) v[which(v>= x[1]& v<= x[2])]
unlist(apply(w, 1, f))
[1] 1 2 5
If you just do the apply() part, the function will return a list of
those elements of v that fall within the i-th interval.
Maybe
> v = c(1, 2, 6, 5)
> start = c(-Inf, 1, 3, 8)
> end = c(-Inf, 4, 5, 10)
> v[ v <= end[findInterval(v, start)] ]
Also IRanges::findOverlaps / countOverlaps in Bioconductor
v[countOverlaps(IRanges(v, v), IRanges(start, end)) != 0]
http://bioconductor.org/install
Martin
HTH,
Dennis
On Fri, Jun 24, 2011 at 9:52 AM, Salih Tuna<saliht...@gmail.com> wrote:
Hi guys,
let's assume i have the following
1
x = 2
6
5
1 4
y = 3 5
8 10
i want the code to report back 1, 2 and 5 from x.
Basically it shopuld check whether each elements of x falls in the
range of
each row of x. 1 and 2 falls in between 1-4 and 5 falls in between 3-5.
I do this with two for loops but in the case of very large list, it
takes
ages.
best,
salih
On Fri, Jun 24, 2011 at 4:12 PM, Dennis Murphy<djmu...@gmail.com> wrote:
Hi:
That leaves open several possibilities. Could you please supply a
small, reproducible example (i.e., one that someone can copy and paste
into an R session) that illustrates the problem along with the
solution you expect?
TIA,
Dennis
On Fri, Jun 24, 2011 at 2:30 AM, Salih Tuna<saliht...@gmail.com> wrote:
Hi Dimitris,
Thanks for your reply. But this is not exactly what i am after. I want
to
find the probes that falls into certain regions. In your solution it
will
ignore the second probe if it falls into the same region as the first
one.
Is there any vector trickb uilt in R to find whether probes fall into
certain regions?
best,
salih
On Fri, Jun 24, 2011 at 10:23 AM, Dimitris Rizopoulos<
d.rizopou...@erasmusmc.nl> wrote:
One approach is the following:
x<- rnorm(5)
y<- matrix(rnorm(5*2), 5, 2)
check<- y - x
check[, 1] * check[, 2]< 0
I hope it helps.
Best,
Dimitris
On 6/24/2011 10:57 AM, Salih Tuna wrote:
Hi All,
What is the fastest way of finding if any members of vector x
fall in
the
range of the rows of matrix y?
I do not want to use two for loops as this will take forever.
Any help will be appreciated,
best,
salih
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--
Dimitris Rizopoulos
Assistant Professor
Department of Biostatistics
Erasmus University Medical Center
Address: PO Box 2040, 3000 CA Rotterdam, the Netherlands
Tel: +31/(0)10/7043478
Fax: +31/(0)10/7043014
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______________________________________________
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
______________________________________________
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
--
Dimitris Rizopoulos
Assistant Professor
Department of Biostatistics
Erasmus University Medical Center
Address: PO Box 2040, 3000 CA Rotterdam, the Netherlands
Tel: +31/(0)10/7043478
Fax: +31/(0)10/7043014
Web: http://www.erasmusmc.nl/biostatistiek/
______________________________________________
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
