Thanks for the clarification. That makes sense. To summarize, bartlett.test() in the base distribution of R is not the sphericity test, and it relies on the higher moments of the normal distribution. The sphericity test can be computed with the formula provided or the one implemented in the psych package, and it does not rely on the higher moments of the normal distribution, but only on the correlation structure between the data.
Peter Dalgaard-2 wrote: > > On Jun 18, 2011, at 15:48 , Tal Galili wrote: > >> Hi Thibault, >> Not that I think you'll use this after the above responses, but for the >> record, have a look at: >> ?bartlett.test > > That's the "other" Bartlett's test, namely the one for comparison of > variances. That test is well known to rely on higher moments of the normal > distribution. > > -- > Peter Dalgaard > Center for Statistics, Copenhagen Business School > Solbjerg Plads 3, 2000 Frederiksberg, Denmark > Phone: (+45)38153501 > Email: pd....@cbs.dk Priv: pda...@gmail.com > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide > http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > -- View this message in context: http://r.789695.n4.nabble.com/Bartlett-s-Test-of-Sphericity-tp3606765p3608160.html Sent from the R help mailing list archive at Nabble.com. ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
