get(a)[[b]][[c]] with
b <- "2011-01-02" Sent from my iPad On Jun 15, 2011, at 9:58, "Franc Lucas" <franc.lu...@web.de> wrote: > > Hello, > I am wondering how to get the quotation marks into a variable expression. I > can't escape it with the backslash \ ... > Example: > I can access my data frame via > TABLE$"2011-01-02"$columnD > Now I want to do this automatically.. (with a for loop).. > a <- TABLE > b <- " \"2011-01-02\" " > c <- "columnD" > acessmytable <- paste(a,b,c, sep="$") > parse(text="accessmytable") > eval(accessmytable) > It will return > [1] "TABLE$\"2011-01-02\"$close" > but I need > TABLE$"2011-01-02"$close > I highly appreciate your help! > Sincerely, > Franc > BS Student, University of Mannheim > > Schon gehört? WEB.DE hat einen genialen Phishing-Filter in die > Toolbar eingebaut! [1]http://produkte.web.de/go/toolbar > > References > > 1. http://produkte.web.de/go/toolbar > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
