On Jun 14, 2011, at 09:53 , Anna Mill wrote: > > Also note that success+failure is exactly 102 in fragment 1 and 105 in > fragment 2, as is the sum of the successes for each fragment (of course it > has to to make exactly 1/4). It is rather easy to suspect that it is actually > a 0/1 coding of the type (as in "tick exactly one box"), and not independent > binomial data. > > sorry for the dumb question: so do you think, that my data is independent and > the model appropriate? > Thanks, Anna >
Well, it's your data, and only you can tell what the original data looks like. We can only _suspect_ that they might be generated to be mutually exclusive. If you do not have independent binomial data, then a glm(..., binomial) will be seriously inappropriate (and a simple chi-square on the table of "successes" by type and fragment will be the obvious thing to do). > > > -- > Peter Dalgaard > Center for Statistics, Copenhagen Business School > Solbjerg Plads 3, 2000 Frederiksberg, Denmark > Phone: (+45)38153501 > Email: pd....@cbs.dk Priv: pda...@gmail.com > > -- Peter Dalgaard Center for Statistics, Copenhagen Business School Solbjerg Plads 3, 2000 Frederiksberg, Denmark Phone: (+45)38153501 Email: pd....@cbs.dk Priv: pda...@gmail.com ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
