I'm analysing some ID50 data for 2 different groups and had already calculated this by hand using Reed-Muench formula, when I came across the dose.p function in R.
I have 2 queries: 1) dose.p gives me a different answer to Reed-Muench, and actually I suspect wrong answer, given that the dose.p result dosage stated to infect 50% is actually stronger than the dose used in my experiments caused above 50% infection! >SetA<-data.frame(c("Hi","Med","Lo"),c(8.44,7.46,6.22),c(31,27,35),c(21,14,6)) >names(SetA)<-c("Group","dose","total","infected") >attach(SetA) >y<-cbind(infected,total-infected) >model<-glm(y~dose,binomial) >library(MASS) > dose.p(model,p=0.5) # Dose SE # > p = 0.5: 7.6056 0.2263418 BUT! The 50% result is Higher than the Med Dose (Log 7.46) which in test produced 51.9% (and by R-M formula the ID50 would be be Log 7.40) 2) How can I compare the ID50's of two sets to see if the difference between their ID50 is signficant? I also have one further Set B and will calculate ID50 for this (by R-M its working out at Log 6.84), and am interested to see if Set A and Set B differ in their ID50. Many thanks in advance -- View this message in context: http://r.789695.n4.nabble.com/ID50-i-comparisons-ii-dose-p-vs-Reed-Muench-tp3579311p3579311.html Sent from the R help mailing list archive at Nabble.com. ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.