Hi Nat,
I guess something like
as.Date(as.character("3/4/2007"),format="%d/%m/%Y")
should work - as.character() coerces the factors to characters, which
the as.Date() function can work with, given the right format argument.
HTH
Stephan
Am 01.06.2011 22:59, schrieb Struckmeier, Nathanael:
I'm trying to convert a column in a data frame with dates from a
"Factor" type to a "Date Object" but I am encountering and error. (I am
having trouble plotting an x,y scatter and I suspect it's something with
my data format). I have a table with two columns and 8,000 rows.
dsort=read.delim("C:\\Documents and Settings\\E066582\\My
Documents\\R\\R-2.13.0\\bin\\dsort.txt")
"dsort" #name of
data.frame
colnames(dsort)[1] #name of column 1
[1] "Date"
colnames(dsort)[2] #name of column 2
[1] "Qty"
class(dsort$Date) #checked data type of column
"Date" and it came back as a factor
[1] "factor"
Date2=as.Date(dsort$Date) #attempt at changing the data type from a
factor to a date object (see error below).
Error in charToDate(x) :
character string is not in a standard unambiguous format
Dates in my table are listed in "3/4/2007" format.
StatBat2
[[alternative HTML version deleted]]
______________________________________________
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
______________________________________________
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.