I am assuming in this case that you are looking for continuity along integers, so if you expect noninteger values this will not work.
You can get the index of where breaks can be found in your example using which(diff(x) > 1) On Wed, Jun 1, 2011 at 6:27 AM, christiaan pauw <cjp...@gmail.com> wrote: > Hallo Everybody > > Consider the following vector > > a=1:10 > b=20:30 > c=40:50 > x=c(a,b,c) > > I need a function that can tell me that there are three set of continuos > sequences and that the first is from 1:10, the second from 20:30 and the > third from 40:50. In other words: a,b, and c. > > regards > Christiaan > > [[alternative HTML version deleted]] > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > -- =============================================== Jon Daily Technician =============================================== #!/usr/bin/env outside # It's great, trust me. ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
