Hi Josh,
You are definitely right. And were all time.
Yes, the problem was always with the write.csv(). I though it was with the "ds".
Thank you very much.
Cheers,
Rui
> Date: Tue, 24 May 2011 14:30:56 -0700
> Subject: Re: [R] How to intantiate a list of data.frames?
> From: jwiley.ps...@gmail.com
> To: ruimax...@hotmail.com
> CC: r-help@r-project.org
>
> Hi Rui,
>
> Please look at the documentation for ?write.csv
>
> I do not have oilDF, but my guess is that you make the object, "ds"
> fine, but then you are trying to pass a list to write.csv which works
> on matrices or data frames (or attempts to coerce to such). The
> easiest answer is probably to write each element of "ds" (that is,
> each data frame) to a separate file.
>
> Cheers,
>
> Josh
>
> On Sun, May 22, 2011 at 12:11 PM, Rui Maximo <ruimax...@hotmail.com> wrote:
> > I will post the whole function, but I believe the problem is in the 3th
> > part.
> > The issue is that oilDF has different number of rows than oilDF2.
> >
> > Thank you,
> > Rui
> >
> > myScan <- function(dirPath, num)
> > {
> > #dirPath is the name of the directory where we want to apply the function.
> > It should be called from the immediate above level without the last 3
> > characters. For example dirPath="oil_0"
> > #num is the mussel number
> >
> > #Heart rate
> > startPath=getwd()
> > workPath=paste(startPath,"/", dirPath,"_HR", sep="")
> > setwd(workPath)
> > temp=dir()
> > d=sort(temp)
> > oilDF=read.table (d[1], header=TRUE)
> > oilDF=data.frame(oilDF[,1], oilDF[,2], oilDF[,num+2])
> > for(i in 2:length(d))
> > {
> > temp <- read.table(d[i], header=TRUE)
> > temp=data.frame(temp[,1], temp[,2], temp[,num+2])
> > colnames(temp) <- colnames(oilDF)
> > oilDF=rbind(oilDF,temp)
> > }
> > setwd(startPath)
> >
> > #Valve Gape
> > workPath=paste(startPath,"/", dirPath,"_VG", sep="")
> > setwd(workPath)
> > temp=dir()
> > d=sort(temp)
> > oilDF2=read.table (d[1], header=FALSE)
> > oilDF2=data.frame(oilDF2[,1],oilDF2[,2],oilDF2[,num+3])
> > for(i in 2:length(d))
> > {
> > temp <- read.table(d[i], header=FALSE)
> > temp=data.frame(temp[,1], temp[,2], temp[,num+3])
> > colnames(temp) <- colnames(oilDF2)
> > oilDF2=rbind(oilDF2,temp)
> > }
> >
> > #Pack both signals in a vector of dataframes for each Mussel.
> > ds <- vector("list", 2)
> > timeHR = as.numeric(strptime(paste(oilDF[,1],oilDF[,2]), "%m/%d/%y
> > %H:%M:%OS"))
> > timeVG = as.numeric(strptime(paste(oilDF2[,1],oilDF2[,2]), "%d/%m/%y
> > %H:%M:%OS"))
> > ds[[1]] <- data.frame(timeHR,oilDF[,3])
> > ds[[2]] <- data.frame(timeVG,oilDF2[,3])
> > write.csv(ds,paste(startPath, "/", "mussel_", i, dirPath, ".csv",
> > sep=""))
> > return(ds)
> > }
> >
> >> Date: Sun, 22 May 2011 11:33:38 -0700
> >> Subject: Re: [R] How to intantiate a list of data.frames?
> >> From: jwiley.ps...@gmail.com
> >> To: ruimax...@hotmail.com
> >> CC: r-help@r-project.org
> >>
> >> Hi Rui,
> >>
> >> data frames must have the same number of rows, but two different data
> >> frames stored within a list do not need to have the same number of
> >> rows. Can you please post the code that is giving the error?
> >>
> >> Josh
> >>
> >> On Sun, May 22, 2011 at 9:41 AM, Rui Maximo <ruimax...@hotmail.com> wrote:
> >> > Hi Josh,
> >> >
> >> > Sorry, your examples have equal number of rows in both df and df2.
> >> > In my situation they haven't.
> >> > Strangely, your solution have worked only when I am copy post the code
> >> > into
> >> > the command line.
> >> > If I use the code inside of a function I get an error at:
> >> > return(ds)
> >> > ERROR: arguments imply differing number of rows
> >> >
> >> > Thanks,
> >> > Rui
> >> >
> >> >> Date: Sat, 21 May 2011 11:46:05 -0700
> >> >> Subject: Re: [R] How to intantiate a list of data.frames?
> >> >> From: jwiley.ps...@gmail.com
> >> >> To: ruimax...@hotmail.com
> >> >> CC: r-help@r-project.org
> >> >>
> >> >> Hi Rui,
> >> >>
> >> >> Here is one option:
> >> >>
> >> >> ds <- vector("list", 6)
> >> >> for(i in 1:6) ds[[i]] <- list(df = mtcars[, c(i, i + 2)], df2 =
> >> >> mtcars[, c(i, i + 2)] + 10)
> >> >>
> >> >> another could be:
> >> >>
> >> >> altds <- lapply(1:6, function(x) {
> >> >> list(df = mtcars[, c(x, x + 2)], df2 = mtcars[, c(x, x + 2)] + 10)
> >> >> })
> >> >>
> >> >> all.equal(ds, altds)
> >> >>
> >> >> For some documentation, see
> >> >>
> >> >> ?vector
> >> >> ?lapply
> >> >>
> >> >> Cheers,
> >> >>
> >> >> Josh
> >> >>
> >> >> On Sat, May 21, 2011 at 10:47 AM, Rui Maximo <ruimax...@hotmail.com>
> >> >> wrote:
> >> >> >
> >> >> > Hello,
> >> >> >
> >> >> > I am newbie to R and I want to do this:
> >> >> >
> >> >> > for(i in 1:6)
> >> >> > {
> >> >> > ds[i] <- list(df=data.frame(oilDF[,1],oilDF[,i+2]),
> >> >> > df2=data.frame(oilDF2[,1],oilDF2[,i+2]))
> >> >> > }
> >> >> >
> >> >> > #oilDF and oilDF2 are 2 data frames with several columns. They have
> >> >> > different number of rows
> >> >> >
> >> >> > #I want to have for example ds[1]$df, ds[1]$df2 with the respective
> >> >> > data.frames.
> >> >> > #How can I instantiate a list of data.frames pairs with different
> >> >> > number
> >> >> > of rows?
> >> >> >
> >> >> > Thank you,
> >> >> > Rui
> >> >> >
> >> >> > [[alternative HTML version deleted]]
> >> >> >
> >> >> > ______________________________________________
> >> >> > R-help@r-project.org mailing list
> >> >> > https://stat.ethz.ch/mailman/listinfo/r-help
> >> >> > PLEASE do read the posting guide
> >> >> > http://www.R-project.org/posting-guide.html
> >> >> > and provide commented, minimal, self-contained, reproducible code.
> >> >> >
> >> >>
> >> >>
> >> >>
> >> >> --
> >> >> Joshua Wiley
> >> >> Ph.D. Student, Health Psychology
> >> >> University of California, Los Angeles
> >> >> http://www.joshuawiley.com/
> >> >
> >>
> >>
> >>
> >> --
> >> Joshua Wiley
> >> Ph.D. Student, Health Psychology
> >> University of California, Los Angeles
> >> http://www.joshuawiley.com/
> >
>
>
>
> --
> Joshua Wiley
> Ph.D. Student, Health Psychology
> University of California, Los Angeles
> http://www.joshuawiley.com/
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