John -
Try
infert[,toolong] = sapply(infert[,toolong],cut2,g=10,levels.mean=TRUE)
- Phil Spector
Statistical Computing Facility
Department of Statistics
UC Berkeley
spec...@stat.berkeley.edu
On Wed, 25 May 2011, Sparks, John James wrote:
Dear R Helpers,
I am having trouble combining some pieces of programming that work fine
individually, but fall down when I try to get them to work together.
The end goal is to take a data frame, and if any of the variables has more
than 10 values, then use cut2 to reduce the number of (effective) values
to 10. I want to do this in automated fashion, which is where the
combining comes in.
For example all of these pieces work as I would expect:
tables<-lapply(infert,table)
lengths<-lapply(tables,length)
toolong<-which(lengths>10)
require(Hmisc)
foo<-as.numeric(cut2(infert$age,g=10,levels.mean=TRUE))
str(foo)
#num [1:248] 2 10 9 7 7 8 1 6 1 3 ...
bar<-paste("inftert$",attr(toolong[1],"names"),sep="")
bar
#[1] "inftert$age"
But the following gives an error:
foobar<-as.numeric(cut2(paste("inftert$",attr(toolong[1],"names"),sep=""),g=10,levels.mean=TRUE))
Error in min(diff(x.unique))/2 : non-numeric argument to binary operator
In addition: Warning message:
In min(diff(x.unique)) : no non-missing arguments, returning NA
Your guidance would be much appreciated.
--John J. Sparks, Ph.D.
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