On May 24, 2011, at 1:34 PM, Phil Spector wrote:
I've always found the chron library to be useful for
tasks like this:
x <- round(runif(10)*100000, digits=0)
y <- as.Date(x, origin="1970-01-01")
library(chron)
days(y)
[1] 7 25 26 25 10 24 1 31 12 8 31 Levels: 1 < 2 < 3 < 4 < 5 < 6 <
7 < 8 < 9 < 10 < 11 < 12 < 13 < ... < 31
Notice that it returns the days as factors.
Could also use as.POSIXlt which is a base function. POSIXlt objects
are internally a list of integers with a day of the month entry:
> as.POSIXlt(y)$mday
[1] 27 24 11 14 17 5 7 16 2 12
So take your pick: character, factor or numeric values can be produced.
--
David.
- Phil Spector
Statistical Computing Facility
Department of Statistics
UC Berkeley
On May 24, 2011, at 10:19 AM, Kang Min wrote:
I have another question -
I'd like to extract dates from a vector of yyyy-mm-dd, so I just want
the dd.
x <- round(runif(10)*100000, digits=0)
y <- as.Date(x, origin="1970-01-01")
I tried this based on the code that Jim provided, but it just printed
the whole date. I think I just need to tweak it a little, but haven't
been able to figure it out.
______________________________________________
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
David Winsemius, MD
West Hartford, CT
______________________________________________
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
