Hi mac, Try
N <- 6000 x <- sample(1:0, N, TRUE) tapply(x, rep(1:(N/60), each = 60), sum) HTH, Jorge On Sat, May 21, 2011 at 1:59 PM, andyjmac <> wrote: > Dear members, > > I apologize for the relatively simple request, but I couldn't find exactly > what I was looking for. I have a binary vector [1,0] representing > presence/absence at 1 second intervals over length(N). I would like to > convert this to a new time series vector with N/60 elements that represent > the sum of x/minute. > > In other words, I'd like to get from: > > e.g. x = [1,0,1,1,0,1,1,1,0,0,0,1,0,1, ... ] *N=6,000 > > to > > e.g. x = [35, 40, 10, 29, ... ] *where each element has min=0 and max=60 > over length N=100 > > Thanks so much, > > mac > Kyoto University, Japan > > -- > View this message in context: > http://r.789695.n4.nabble.com/convert-binary-vector-to-time-series-of-sum-x-minute-tp3540942p3540942.html > Sent from the R help mailing list archive at Nabble.com. > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide > http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > [[alternative HTML version deleted]] ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
