Kalicin, Sarah wrote:
\begin{quote}
I have a work around for this, but can someone explain
why the first example does not work properly?
I believed it worked in the previous version of R,
by selecting just the rows=200525 and omitting the na's.
\end{quote}
You can prove this statement by providing reproducible
code that we can test.
Peter Ehlers
I just upgraded to 2.13. I am also concern with the row numbers being
different in the selections, should I be worried? FYI, I just selected
the first few rows for demonstration, please do not worry that the
number of rows shown are not equal. - Sarah
With na.omit around the column, but it is showing other values in the F.WW
column other than 200525, along with NA. I was hoping that this would omit all
the NA's, and show all the rows that P$F.WW=200525. I believe it did with the
previous version of R.
P[na.omit(P$F.WW)==200525, c(51, 52)]
F.WW R.WW
45 200525 NA
53 NA NA
61 200534 200534
63 200608 200608
66 200522 200541
80 NA NA
150 200521 200516
231 200530 200530
No na.omit, the F.WW=200525 seems to work, but lots of NA included. This is
what is expected!! The row numbers are not the same as the above example,
except the first row.
P[P$F.WW==200525, c(51, 52)]
F.WW R.WW
45 200525 NA
NA NA NA
NA.1 NA NA
NA.2 NA NA
NA.3 NA NA
57 200525 200526
65 200525 NA
67 200525 NA
70 200525 200525
NA.4 NA NA
NA.5 NA NA
86 200525 NA
Na.omit excludes the na's. This is what I want. The concern I have is why the
row numbers do not match any of those shown in the examples above.
na.omit(P[P$F.WW==200525, c(51, 52)])
F.WW R.WW
57 200525 200526
70 200525 200525
161 200525 200525
245 200525 200525
246 200525 200525
247 200525 200526
256 200525 200525
266 200525 200525
269 200525 200525
271 200525 200526
276 200525 200526
278 200525 200526
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