x/rep(divs,each=1000)
cheers,
Rolf Turner
On 25/02/2008, at 2:36 PM, Andre Nathan wrote:
> Hello,
>
> I have a vector of 1,000,000 numbers and another vector of 1,000
> divisors. What I'd like to do is to divide the first 1,000 numbers of
> the first vector by the first divisor, then the next 1,000 by the
> second
> divisor and so on. I came up with this, but I was wondering if
> there is
> a more idiomatic, R-like way to write it:
>
> x <- ...
> divs <- ...
>
> for (i in seq(from = 1, to = 1000000, by = 1000)) {
> x[i:(i - 1 + 1000)] <- x[i:(i - 1 + 1000)] / divs[i %/% 1000 + 1]
> }
>
> Any suggestions are welcome.
>
> Thanks in advance,
> Andre
>
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