On Apr 19, 2011, at 6:59 AM, santosh wrote:

Dear Group,

I am doing an apply function on a zoo object. I need the rownames to
be passed to the function.
Any suggestions on how to accomplish this?

Here is the code I am using

tmp <-
structure(c(611.55, 611.55, 611.55, 611.55, 611.55, 520, 520,
520, 520, 520, 425, 425, 425, 432.2, 432.2, 337, 338, 328.95,
328.95, 328.95, 243.8, 242.775, 238.5, 239, 235.925, 161.7, 156.625,
152.825, 151.95, 151.9, 1.5, 1.5, 1.5, 1.5, 1.5, 2, 2.15, 2.15,
2, 2, 3, 2.95, 3.175, 3.2, 3.15, 6, 6.15, 6.525, 6.6, 6.6, 14.5,
14.5, 15.15, 15.45, 15.3, 32.05, 32.05, 33.09, 33.8, 33.23), .Dim =
c(5L,
12L), .Dimnames = list(c("2011-04-19 09:24:30", "2011-04-19
09:25:00",
"2011-04-19 09:25:30", "2011-04-19 09:26:00", "2011-04-19 09:26:30"
), c("A", "B", "C", "D", "E", "F", "G", "H", "I", "J", "K", "L"
)), index = structure(c(1303185270, 1303185300, 1303185330,
1303185360,
1303185390), class = c("POSIXt", "POSIXct"), tzone = ""), class =
"zoo")


tmp
                     A   B   C   D   E   F   G    H    I    J    K
L
2011-04-19 09:24:30 612 520 425 337 244 162 1.5 2.00 3.00 6.00 14.5
32.0

snipped

apply(tmp,1,function(x)(print (rownames(x))))
NULL
NULL
snipped
#How can I get the rownames here instead?

> rownames(tmp)
[1] "2011-04-19 09:24:30" "2011-04-19 09:25:00"
[3] "2011-04-19 09:25:30" "2011-04-19 09:26:00"
[5] "2011-04-19 09:26:30"

(apply() removes the rownames before passing rows on to functions, ... since they are no longer rows but rather vectors at that point.)

--
David Winsemius, MD
West Hartford, CT

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