Long story short, I have a big iterative procedure that produces a long list of
data.frames such as the one called
"results" here. Is there an easy way to produce a similar list of data.frames
comprised of the mean of each of the
columns in results, such that it ends up like the one I've shown in
"resultsmean" below?
I've tried apply and lapply, still not got the correct arguments. As usual,
TIA.
Jim
> results
[[1]]
name LOR23 BIA23 MSE23 H0R23
1 0.2111122 -1.012228 -0.095937 0.035650 1.00
2 0.2111122 -0.836300 0.079991 0.042322 0.75
3 0.2111122 -0.518631 0.397659 0.214593 0.50
[[2]]
name LOR23 BIA23 MSE23 H0R23
1 0.2211122 -0.724630 0.191660 0.051308 1
2 0.2211122 -0.781812 0.134478 0.033872 1
3 0.2211122 -0.522109 0.394181 0.164628 0.75
would like
> resultsmean
[[1]]
name LOR23 BIA23 MSE23 H0R23
1 0.2111122 -0.78333 0.12734 0.097160 0.75
[[2]]
name LOR23 BIA23 MSE23 H0R23
1 0.2211122 -0.67566 0.2400 0.08266 0.916
===============================
Dr. Jim Maas
University of East Anglia
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