On 21-Feb-08 20:58:25, Evgenia wrote:
>
> Dear R users,
> I would like to sample from a mixture distribution
> p1*f1+p2*f2+p3*f3 with f1,f2,f3 three different forms
> of distributions. I know that in the case of two
> distributions I have to sample the mixture compoment
> membership.
>
> How can I weight my three distributions with their
> respective probabilities?
>
> Evgenia
There are several ways in which you could write code
to do this, but all amount to the fact that each value
sampled from such a mixture is obtained by
a) choose between f1, f2, f3 at random according to the
probabilities p1, p2, p3 (it is assumed p1+p2+p3=1).
b) sample 1 value from whichever of f1, f2, f3 was chosen.
Suggestion:
Suppose the functions rf1(n), rf2(n), rf3(n) respectively
sample n values from f1, f2 and f3.
S0 <- cbind(rf1(n),rf2(n),rf3(n))
ix <- sample(c(1,2,3),n,3,prob=c(p1,p2,p3),replace=TRUE)
S <- S0[,ix]
will produce n values, each of which is a sample of size 1
from the mixture.
Example:
rf1 <- function(n){rnorm(n,0,1)} ## normal distribution with mean=0
rf2 <- function(n){rnorm(n,4,1)} ## normal distribution with mean=4
rf3 <- function(n){rnorm(n,9,1)} ## normal distribution with mean=9
p1 <- 0.2; p2 <- 0.3; p3 <-0.5
S0 <- cbind(rf1(500),rf2(500),rf3(500))
ix <- sample(c(1,2,3),500,prob=c(p1,p2,p3),replace=TRUE)
S <- S0[,ix]
hist(S,breaks=50)
Hoping this helps.
Ted.
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E-Mail: (Ted Harding) <[EMAIL PROTECTED]>
Fax-to-email: +44 (0)870 094 0861
Date: 21-Feb-08 Time: 21:39:53
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