On Wed, Apr 6, 2011 at 3:40 PM, Bogaso Christofer
<bogaso.christo...@gmail.com> wrote:
> Dear all, please consider my following workbook:
>
>
>
> library(zoo)
>
> lis1 <- vector('list', length = 2)
>
> lis2 <- vector('list', length = 2)
>
> lis1[[1]] <- zooreg(rnorm(20), start = as.Date("2010-01-01"), frequency = 1)
>
> lis1[[2]] <- zooreg(rnorm(20), start = as.yearmon("2010-01-01"), frequency =
> 12)
>
>
>
> lis2[[1]] <- matrix(1:40, 20)
>
> lis2[[2]] <- matrix(41:80, 20)
>
>
>
> Now I want to make each element of 'lis2' as zoo object where the
> corresponding indices will be borrowed from 'lis1'. This means:
>
>
>
> for (i in 1:2) {
>
> lis2[[i]] <- zoo(lis2[[i]],
> index(lis1[[i]]))
>
> }
>
>
>
> However is there any faster way to do that? I found that if the sizes of
> lis1 & lis2 is quite big then it takes lot of time to complete.
>
Try this:
mapply(function(mat, z) zoo(mat, time(z)), lis2, lis1, SIMPLIFY = FALSE)
or this:
mapply(zoo, lis2, lapply(lis1, time), SIMPLIFY = FALSE)
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