Hello List. I have many files of ECG, each one with 7 column and I need only the second column and the name of each ECG. I am doing this but althought I have various days trying this i haven't gotten, so I ask help with this, if somebody cans help me I'll be so thankfully.
-------------------------------------------------------------------------------------------------------- rm(list=ls()) # loadEcgFiles <- function(Dir=".") { Dir <- "."; txtfiles <- list.files(paste(Dir),'.txt$'); ecg = data.frame(ncol=1); len = length(txtfiles); for (i in 1:5 ) { # i <- 1; filename = paste(projectDir, "/" , txtfiles[i],sep=''); sample = read.table(filename, nrow=75000); sampleName = filename; sampleName=gsub("./", "",sampleName); sampleName=gsub(".txt", "", sampleName); temp <- sample$V2; names(temp) <- sampleName; ecg = cbind(ecg, temp); # } Thanks and sorry for my english. --- Marcos Amaris González - Linux Counter #462840 ------------------------------------------------------------------------------ No al SPAM! "No es más rico el que más tiene, sino el que menos necesita." ------------------------------------------------------------------------------ ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.