You get 0 because you did not specify lower and upper bounds that define the
hyper-rectangle; therefore, the default is used which is (0,1)^4.
Specify the proper lower and upper bounds.
Ravi.
____________________________________________________________________
Ravi Varadhan, Ph.D.
Assistant Professor,
Division of Geriatric Medicine and Gerontology
School of Medicine
Johns Hopkins University
Ph. (410) 502-2619
email: rvarad...@jhmi.edu
----- Original Message -----
From: Dmlong21 <dml...@bios.unc.edu>
Date: Tuesday, March 29, 2011 3:11 pm
Subject: Re: [R] Integration with variable bounds
To: r-help@r-project.org
> Thanks for the tip but all I get is 0 for the integral. Any other
> suggestions?
>
> int <- function(y){
> u2 = y[1]
> z2 = y[2]
> u1 =y[3]
> z1 = y[4]
>
> reg.nonzero <- (u2 > z1 & u2 < z2) & (z2 > z1 & z2 < 12) & (u1 > 4 &
> u1 <
> z1) & (z1 > 4 & z1 < 12)
>
>
> ff <- ifelse (reg.nonzero, u1*(z1-u1)*u2*(z2-u2)*exp(-0.027*(12-z2)),
> 0)
>
>
> return(ff)
>
>
> }
>
>
> cuhre(4,1,int)
>
> --
> View this message in context:
> Sent from the R help mailing list archive at Nabble.com.
>
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> R-help@r-project.org mailing list
>
> PLEASE do read the posting guide
> and provide commented, minimal, self-contained, reproducible code.
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