Hi Rita,

This is far from the most efficient or elegant way, but:

## two column data frame, one all NAs
d <- data.frame(1:10, NA)
## use apply to create logical vector and subset d
d[, apply(d, 2, function(x) !all(is.na(x)))]

I am just apply()ing to each column (the 2) of d, the function
!all(is.na(x)) which will return FALSE if all of x is missing and TRUE
otherwise.  The result is a logical vector the same length as the
number of columns in d that is used to subset only the d columns with
at least some non-missing values.  For documentation see:

?apply
?is.na
?all
?"["
?Logic

HTH,

Josh

On Fri, Mar 18, 2011 at 3:35 PM, Rita Carreira <ritacarre...@hotmail.com> wrote:
>
> Dear List Members,I have 55 data frames, each of which with 272 variables and 
> 267 observations. Some of these variables are blanks but the blanks are not 
> the same for every data frame. I would like to write a procedure in which I 
> import a data frame, see which variables are blank, and delete those 
> variables. My data frames have variables named P1 to P136 and Q1 to Q136.
> I have a couple of questions regarding this issue:
> 1) Is a loop an efficient way to address this problem? If not, what are my 
> alternatives and how do I implement them?2) I have been playing with a single 
> data frame to try to figure out a way of having R go through the columns and 
> see which ones it should delete. I have figured out how to delete rows with 
> missing data (newdata <- na.omit(olddata)) but how do I do it for columns???
> Thank you very much for your help and have a great weekend!
> Rita ________________________________________ "If you think education is 
> expensive, try ignorance"--Derek Bok
>
>
>
>        [[alternative HTML version deleted]]
>
> ______________________________________________
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>



-- 
Joshua Wiley
Ph.D. Student, Health Psychology
University of California, Los Angeles
http://www.joshuawiley.com/

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