Hello R community,
I have two questions about using R.
The first is about dividing each element of a list with another similar
sized list. So, if the first list has two elements and so does the second,
then the result should also be a list with two elements.
For example, the inputs are:
list(matrix(1:6,ncol=2),matrix(1:6,ncol=2))->l1
l2<-list(1:3,2)
I want to get a list, l3 with the first element being l1[[1]]/l2[[1]] and
the second one, l1[[2]]/l2[[2]].
I had asked a similar question before and the solution using mapply works
well for a list and a vector, but for two lists, it will return an array
(and not a list).
My second question is about the tapply function.
tapply(1:5,list(c(1,1,2,2,3),c(1,2,1,1,3)),sum)
will give me:
1 2 3
1 1 2 NA
2 7 NA NA
3 NA NA 5
The index here is a list: list(c(1,1,2,2,3),c(1,2,1,1,3)).
However, if I get the same index list through one of the other apply
functions (like by) for example,
indxLi<-by(rbind(c(1,1,2,2,3),c(1,2,1,1,3)),1:2,function(x){return(x)})
then the tapply no longer works with this list.
tapply(1:5,indxLi,sum) gives me the error:
Error in sort.list(y) : 'x' must be atomic for 'sort.list'
Have you called 'sort' on a list?
Is there a way to use the above list in the tapply function?
Many thanks in advance,
--
Thanks,
Rohit
Mob: 91 9819926213
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