It is easy to recover the date by using as.Date: > dat <- matrix(seq(as.Date("2011-01-01"), as.Date("2011-01-09"), by="1 day"), > 3) > dat [,1] [,2] [,3] [1,] 14975 14978 14981 [2,] 14976 14979 14982 [3,] 14977 14980 14983 > str(dat) num [1:3, 1:3] 14975 14976 14977 14978 14979 ... > as.Date(dat) [1] "2011-01-01" "2011-01-02" "2011-01-03" "2011-01-04" "2011-01-05" "2011-01-06" "2011-01-07" "2011-01-08" [9] "2011-01-09" >
On Fri, Mar 11, 2011 at 4:15 PM, Bogaso Christofer <bogaso.christo...@gmail.com> wrote: > Dear all, when I put date objects (class of 'Date') in a matrix it becomes > numeric: > >> dat <- matrix(seq(as.Date("2011-01-01"), as.Date("2011-01-09"), by="1 > day"), 3) > >> dat > > [,1] [,2] [,3] > > [1,] 14975 14978 14981 > > [2,] 14976 14979 14982 > > [3,] 14977 14980 14983 > >> class(dat[1,1]) > > [1] "numeric" > > > > As it could not preserve the 'Date' characteristics after putting my Date > observations, I find it difficult to carry forward further calculation with > Dates. Can somebody help me on how to preserve the Data properties while > storing them within some matrix? > > > > Thanks > > > [[alternative HTML version deleted]] > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > -- Jim Holtman Data Munger Guru What is the problem that you are trying to solve? ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.