Hello, no. I need to change data format, so i can build covariance matrix on it
Cheers, Dima 2011/3/4 Alberto Negron <albertoneg...@gmail.com> > Can't you just convert you df as follow matrix <- as.matrix(s) ? > > Double check it as I am a newbie too. :-) > > Regards, > > Alberto > > On 4 March 2011 06:08, Dmitrij Kudriavcev <dimitrij.kudriav...@ntsg.lt>wrote: > >> Hello >> >> I'm a new in R >> I have a large data.frame "s" (this is actualy just a table in mysql) : >> >> > names(s) >> [1] "symbols", "day", "value" >> >> I need to convert it to simple matrix. I have define this matrix like >> this: >> >> > data.matrix <- matrix(nrow=nDays, ncol=nSymbols, dimnames=list(days, >> symbols)) >> >> then i just copy values to the matrix using for() loop, but it seems to >> take >> very long time. Is is a more fast way to do it in R? I know, what i can >> just >> gyve s$value as source data to the matrix, but problem is, what for some >> symbols couple days could be just missed. >> >> Cheers, >> Dima >> >> [[alternative HTML version deleted]] >> >> ______________________________________________ >> R-help@r-project.org mailing list >> https://stat.ethz.ch/mailman/listinfo/r-help >> PLEASE do read the posting guide >> http://www.R-project.org/posting-guide.html >> and provide commented, minimal, self-contained, reproducible code. >> > > [[alternative HTML version deleted]] ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
