On Mon, Feb 7, 2011 at 9:37 AM, Roy Mathew <roymathe...@gmail.com> wrote:
> Dear R Users,
>
> if I have a string as follows
> x<-"jsda23tth"
>
> How can I extract out 23 as a numeral?
> I found
> substr(x,5,6)
> but, this doesnt work if the number of alphabets differ.
>
> This is another example where the numbers need to be extracted.
> x<-c("jsda23tth","fgd54fgd","j3ngh","gfdjh564")
>
> any ideas?
>
> This didnt work.
> grep("[/d]",x)
Here are a couple of solutions:
> as.numeric(gsub("\\D", "", x))
[1] 23 54 3 564
> library(gsubfn)
> strapply(x, "\\d+", as.numeric, simplify = TRUE)
[1] 23 54 3 564
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