You can use the summary with the split argument. See ?summary.aov for an example.
This gives similar results to the regression coefficients approach that Ista Zahn suggested. I usually prefer the ANOVA table approach for factors. On Thu, Feb 3, 2011 at 3:36 AM, Asan Ramzan <asanram...@yahoo.com> wrote: > Hello R-help > I dont know how to interpret significance from the contr.poly() function . [[alternative HTML version deleted]]
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