On Tue, Feb 1, 2011 at 9:23 AM, Peter Ehlers <ehl...@ucalgary.ca> wrote:
> Will this suffice:
>
> dotchart(c(table(infert$education)))
That is probably the cleanest answer for now (I tried something like
that with as.vector(), but lost the names). Another reasonable option
would be:
dotchart(unclass(table(infert$education)))
2D tables work fine presently: dotchart(table(state.division, state.region))
I started a thread on R-devel suggesting a few possible solutions, so
perhaps in the next release, dotchart() will be able to handle table
class objects without any coercion.
Josh
>
> Peter Ehlers
>
>>
>>
>> Cheers,
>>
>> Josh
>>
>> On Tue, Feb 1, 2011 at 6:52 AM, Van Patten, Isaac T
>> <ivanp...@radford.edu> wrote:
>>>
>>> I have a factor vector of subject races (Asian, Black, Hispanic, White;
>>> n=30) that I want to plot with a Cleveland dotplot or dotchart.
>>>
>>> I tried the following in R2.12.1 :
>>>
>>>> dotchart(table(school$Race))
>>>
>>> Error in plot.xy(xy.coords(x, y), type = type, ...) : invalid plot type
>>>
>>> Using the same data set in R2.11.1 the operation succeeded (I tried
>>> several variations to be sure):
>>>
>>>> dotchart(table(school$Race))
>>>> race2<-table(school$Race)
>>>> dotchart(race2)
>>>> dotchart(race2, pch=17,col="red")
>>>
>>> Each of these worked in 2.11.1 but not in 2.12.1; What changed in the
>>> {graphics} package to alter this and is there a work-around?
>>>
>>> Isaac T. Van Patten, Ph.D.
>>> Professor of Criminal Justice
>>> 307 Adams Street, Office 1A
>>> Box 6934, Radford University
>>> Radford, VA 24142
>>> (540)831-6737
>>> ivanp...@radford.edu
>>> http://ivanpatt.asp.radford.edu
>>> It doesn't matter how beautiful your theory is;
>>> It doesn't matter how smart you are;
>>> If it doesn't agree with the [data], its wrong.
>>> -Richard Feynman
>>>
>>> ______________________________________________
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>>> https://stat.ethz.ch/mailman/listinfo/r-help
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