Sorry if I did not clarify that. Here I have a data frame with many columns,
which was taken from some outside DB. Now I want to split that data frame
and create a "list" object (to make my further calculation easier), on basis
of a typical column of that DB. I cannot post my original DB here (due to
some security reason and ofcourse it's huge size), therefore I posted an
artificial DB.
Here my artificial DB with 3 columns:
dfrm <- data.frame(x=rnorm(18), y=rep(c("a", "b", "c"), each=6),
z=rep(c("x", "y", "z"), each=2))
I would like to create a list object where each element now is a matrix or
data frame, based on that "y" column. 1st element of that list will be a
data frame with observations of "x" and "z" columns, that address the
attribute "y = a". Similarly other two.
Hope I could be able to make my intentions clearer.
Any idea how I can achieve that?
Thanks,
-----Original Message-----
From: David Winsemius [mailto:dwinsem...@comcast.net]
Sent: 01 February 2011 00:13
To: Bogaso Christofer
Cc: r-help@r-project.org
Subject: Re: [R] From data frame to list object
On Jan 31, 2011, at 1:56 PM, Bogaso Christofer wrote:
> Thanks David for this reply. However if my data frame has only 2
> columns
> then it is working fine. It is not working for a general setting:
>
> dfrm <- data.frame(x=rnorm(18), y=rep(c("a", "b", "c"), each=6),
> z=rep(c("x", "y", "z"), each=2))
> tapply(dfrm[,1], dfrm$y, c) # this is working fine
>
>> tapply(dfrm[,c(1,3)], dfrm$y, c) # this is giving error!
> Error in tapply(dfrm[, c(1, 3)], dfrm$y, c) :
> arguments must have same length
>
> Can you please help me how to modify that?
You will need to specify what you goals are. What to you want to
happen to those two columns referred to by dfrm[, c(1,3)]? It's
possible that split() may be the answer, but clarify the goals first.
You should provide an example that represents the complexity of the
task.
>
> Thanks,
>
> -----Original Message-----
> From: David Winsemius [mailto:dwinsem...@comcast.net]
> Sent: 31 January 2011 23:26
> To: Bogaso Christofer
> Cc: r-help@r-project.org
> Subject: Re: [R] From data frame to list object
>
>
> On Jan 31, 2011, at 1:03 PM, Bogaso Christofer wrote:
>
>> Dear all, let say I have following data frame:
>>
>>
>
>> dfrm <- data.frame(x=rnorm(18), y=rep(c("a", "b", "c"), each=6)) >
> tapply(dfrm$x, dfrm$y, c) $a [1] 0.9711995 1.4018345 -1.4355713
> -0.5106138
> -0.8470171 [6] 1.1634586
>
> $b
> [1] -0.8058164 0.4977112 1.1556391 0.8158588 0.2549273 [6]
> 3.0758260
>
> $c
> [1] 0.437345128 -0.415874363 0.003230285 -0.737117910 [5]
> 1.247972964
> 0.903001077
>
>
>>
>>> data.frame(x=rnorm(18), y=rep(c("a", "b", "c"), each=6))
>>
>> x y
>>
>> 1 -1.072152537 a
>>
>> 2 0.382985265 a
>>
>> 3 0.058877377 a
>>
>> 4 -0.006911939 a
>>
>> 5 -2.355269051 a
>>
>> 6 -0.303095553 a
>>
>> 7 0.484038422 b
>>
>> 8 0.733928931 b
>>
>> 9 -1.136014346 b
>>
>> 10 0.503552090 b
>>
>> 11 1.708609658 b
>>
>> 12 -0.294599403 b
>>
>> 13 1.239308497 c
>>
>> 14 0.754081946 c
>>
>> 15 -0.237346858 c
>>
>> 16 -0.051011439 c
>>
>> 17 -0.618675146 c
>>
>> 18 0.537612359 c
>>
>>
>>
>>> From this data frame I want to create a "list" of length 3, where
>>> each
>> element of this list will be a vector corresponding to the value of
>> y.
>> For example, 1st element will be all "x" values corresponding to the
>> "y=a", and similarly the other elements of this list. Can somebody
>> point me how to do this without having some "for" loop?
>>
>>
>>
>> Thanks and regards,
>>
>>
>> [[alternative HTML version deleted]]
>>
>> ______________________________________________
>> R-help@r-project.org mailing list
>> https://stat.ethz.ch/mailman/listinfo/r-help
>> PLEASE do read the posting guide
>> http://www.R-project.org/posting-guide.html
>> and provide commented, minimal, self-contained, reproducible code.
>
> David Winsemius, MD
> West Hartford, CT
>
David Winsemius, MD
West Hartford, CT
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