I would leave off the as.character(). With it you get
things like:
> f <- rpart(Kyphosis ~ ., kyphosis[-3])
> as.list(f$call)$data
kyphosis[-3]
> as.character(as.list(f$call)$data)
[1] "[" "kyphosis" "-3"
Expressions like quote(kyphosis[-3]) are much
easier to analyze as expressions that as vectors
of character strings. E.g., you can use all.vars
on an expression to see what variables are mentioned
in it.
When it is time to print the expression you may
need to use deparse() to turn it into a readable
vector of strings.
Bill Dunlap
Spotfire, TIBCO Software
wdunlap tibco.com
________________________________
From: Tal Galili [mailto:[email protected]]
Sent: Wednesday, January 26, 2011 11:35 AM
To: Henrique Dallazuanna
Cc: [email protected]; William Dunlap
Subject: Re: [R] Extracting the terms from an rpart object
Exactly what I needed Henrique,
Thank you.
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On Wed, Jan 26, 2011 at 8:26 PM, Henrique Dallazuanna
<[email protected]> wrote:
Try this:
as.character(as.list(fit1$call)$data)
On Wed, Jan 26, 2011 at 4:12 PM, Tal Galili
<[email protected]> wrote:
Another (similar) question,
If I now want to know the name of the "data" argument
used, is there an easy way for me to access it?
I'm trying to use something like:
eval(parse(text = all.vars(terms(fit1))[1]))
Which (of course) wouldn't work, since the response
variable is only available in the data used by rpart (specifically the
"kyphosis" dataset)
Thanks upfront.
Tal
----------------Contact
Details:-------------------------------------------------------
Contact me: [email protected] | 972-52-7275845
Read me: www.talgalili.com (Hebrew) |
www.biostatistics.co.il (Hebrew) | www.r-statistics.com (English)
----------------------------------------------------------------------------------------------
On Wed, Jan 26, 2011 at 7:40 PM, Henrique Dallazuanna
<[email protected]> wrote:
Try this:
all.vars(terms(fit1))
all.vars(terms(fit2))
On Wed, Jan 26, 2011 at 3:33 PM, Tal Galili
<[email protected]> wrote:
Hello all,
I wish to extract the terms from an
rpart object.
Specifically, I would like to be able
to know what is the response variable
(so I could do some manipulation on it).
But in general, such a method for rpart
will also need to handle a "." case
(see fit2)
Here are two simple examples:
fit1 <- rpart(Kyphosis ~ Age + Number +
Start, data=kyphosis)
fit1$call
fit2 <- rpart(Kyphosis ~ .,
data=kyphosis)
fit2$call
Is there anything "prettier" then using
string manipulation?
Thanks.
----------------Contact
Details:-------------------------------------------------------
Contact me: [email protected] |
972-52-7275845
Read me: www.talgalili.com (Hebrew) |
www.biostatistics.co.il (Hebrew) |
www.r-statistics.com (English)
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--
Henrique Dallazuanna
Curitiba-Paraná-Brasil
25° 25' 40" S 49° 16' 22" O
--
Henrique Dallazuanna
Curitiba-Paraná-Brasil
25° 25' 40" S 49° 16' 22" O
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______________________________________________
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
