On Tue, 12 Feb 2008, Peter Holck wrote: > Using the survey package I find it is convenient and easy to get estimated > proportions using svymean, and their corresponding estimated standard > errors. But is there any elegant/simple way to calculate corresponding > confidence intervals for those proportions? Of course +/- 1.96 s.e. is a > reasonable approximation for a 95% CI, but (incorrectly) assumes symmetrical > distribution for a proportion.
'Incorrectly' is a bit strong, I think. > About all I can think of is to transform onto some scale like the logit > scale, use the delta method to estimate standard errors, and transform back > for appropriate confidence intervals. Or perhaps use the machinery of the > survey package svyglm function with logit link (family=quasibinomial) to do > the calculations for me. Still, seems rather cumbersome. Is there a better > solution? > I think the most straightforward solution would be svyglm(). You could also use svycontrast() to do the delta-method calculations for you. -thomas Thomas Lumley Assoc. Professor, Biostatistics [EMAIL PROTECTED] University of Washington, Seattle ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.