Here is a hack, crude solution to get the digits: Digits <- function(a){ out <- rep(NA,nchar(a)) for(i in 1:nchar(a)) out[i] <- substr(a,i,i) return(as.numeric(out)) }
Digits(183429) If all you want is the last three numbers, consider another hack solution: Last3Digits <- function(a) as.numeric(substr(a,nchar(a)-2,nchar(a))) Last3Digits(23495329) Hope that helps. These are hack solutions, and I'm willing to bet there is better stuff available. -tgs On Sun, Jan 23, 2011 at 1:39 PM, Quan Zhou <quan.poko2...@gmail.com> wrote: > Hi Everyone, > A quick question how to store a number like 12345 to a vector or array with > size(1,5), like 1, 2, 3, 4, 5 > So I can compare if the last three digits of this number is the same with > some other numbers. > > Thanks a lot > > [[alternative HTML version deleted]] > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide > http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > [[alternative HTML version deleted]] ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.