> -----Original Message-----
> From: r-help-boun...@r-project.org
> [mailto:r-help-boun...@r-project.org] On Behalf Of Sean Zhang
> Sent: Thursday, January 13, 2011 4:37 PM
> To: r-help@r-project.org
> Subject: [R] question about deparse(substitute(...))
>
> Dear R helpers:
>
> I like to apply deparse(substitute()) on multiple arguments
> to collect the
> names of the arguments into a character vector.
> I used function test.fun as below. it works when there is
> only one input
> argument. but it does not work for multiple arguements. can
> someone kindly
> help?
>
> test.fun <- function(...){deparse(substitute(...))}
> test.fun(x) #this works
> test.fun(x,y,z) # I like c('x','y','z') be the output, but
> cannot get it.
One way is:
> f <- function(...) lapply(substitute(placeholderFunction(...))[-1],
deparse)
> f(x, log(y), (function(a){a+a^2/2+a^3/6})(z))
[[1]]
[1] "x"
[[2]]
[1] "log(y)"
[[3]]
[1] "(function(a) {"
[2] " a + a^2/2 + a^3/6"
[3] "})(z)"
Use paste(collapse="\n",s) or s[1] on
deparse's output if you require one
string per input.
Bill Dunlap
Spotfire, TIBCO Software
wdunlap tibco.com
>
> Thanks in advance.
>
> -Sean
>
> [[alternative HTML version deleted]]
>
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