On Jan 12, 2011, at 10:54 PM, Sebastián Daza wrote:
Hi everyone,
I am new in R and programming. I have tried to remove the values out
of range in some variables using a loop:
1)
var <- names(est8vo[, 77:83]) # I got the variable names
> var
[1] "p16.1" "p16.2" "p16.3" "p16.4" "p16.5" "p16.6" "p16.7"
for (i in 1:7) {
var.i <- var[i]
est8vo$var.i[ est8vo$var.i==3] <- 99
You CANNOT use names like that. (It makes no sense to supply a vector
argument to "$".) If you want to change every instance of 3 within a
group of columns. See if this works
est8vo[, 77:83] <- sapply( est8vo[, 77:83], function(x) ifelse(x==3,
99, x) )
}
I got this error:
Error in `$<-.data.frame`(`*tmp*`, "var.i", value = numeric(0)) :
replacement has 0 rows, data has 215700
2) The second step would be to define the factors, but I got the
same error:
est8vo[, 77:83] <- sapply(est8vo[, 77:83] , factor, labels=c("vacío",
"sí", "no", "doble marca"))
for (i in 1:7) {
var.i <- var[i]
est8vo$var.i <- factor(est8vo$var.i,
Wrong. Wrong. Wrong. And please forget about using "$" inside loops in
the left-hand side. It is not designed for that.
levels=c(0, 1, 2, 99),
labels=c("vacío", "sí", "no", "doble marca")
)
}
I don't know how to do it.
Thank you in advance!
Sebastian
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______________________________________________
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
