On Wed, Dec 29, 2010 at 12:31 PM, Patrick McKann <pcmck...@gmail.com> wrote: > I seem to come to this problem alot, and I can find my way out of it with a > loop, but I wish, and wonder if there is a better way. Here's an example > (lmer1-5 are a series of lmer objects): > > bs=data.frame(bic=BIC(lmer1,lmer2,lmer3,lmer4,lmer5)$BIC) > rownames(bs)=c('lmer1','lmer2','lmer3','lmer4','lmer5') > best=rownames(bs)[bs==min(bs)] > >> best > [1] "lmer5" > > This tells me that lmer5 is the model with the lowest BIC. I want to start > working with lmer5 as the best model, such as fixef(best) to get the fixed > effect estimates from lmer5. I tried best=as.object('lmer5') but of course > this doesn't work because that is not a real function. > > Does anybody see what I'm getting at? If so, do you know a way to do this > without a loop or series of if statements? >
If you are asking how to turn a string into a variable its a FAQ! http://cran.r-project.org/doc/FAQ/R-FAQ.html#How-can-I-turn-a-string-into-a-variable_003f -- Statistics & Software Consulting GKX Group, GKX Associates Inc. tel: 1-877-GKX-GROUP email: ggrothendieck at gmail.com ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.