Hello Ufuk,
Here is one way to do it...
# make up some data for this example
x <- matrix(runif(7 * 20), ncol=7)
# a data.frame is most convenient for lm
x <- as.data.frame(x)
colnames(x) <- c("x1", "x2", "x3", "x4", "x5", "x6", "y")
# a list to hold lm results
x.lm <- list()
# run regressions
for (i in 1:nrow(x)) {
x.lm <- c(x.lm, list( lm(y ~ ., data=x[-i, ]) ))
}
Now element i of x.lm will hold the results of the regression with
data row i removed.
Michael
On 23 December 2010 08:57, ufuk beyaztas <ufukbeyaz...@gmail.com> wrote:
>
> Hi dear all,
>
> suppose that s is a statistic code;
>
> i have a matrix (x) which has 7 columns (1=x1,2=x23=x3,4=x4,5=x5,6=x6
> and7=y)
> and has 20 rows. i want to do linear reggression like
> reg<-lm(x[,7]~1+x[,1]+x[,2]+.......+x[,6])
> but i want to do delete i th row for nrows times and create regression model
> like above and compute each models' "s" statistics and list them. but i
> could not do. i always get only one model and statistic.
> How can i do this
>
> Thanks any idea!
> --
> View this message in context:
> http://r.789695.n4.nabble.com/regression-tp3161328p3161328.html
> Sent from the R help mailing list archive at Nabble.com.
>
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