Hi Serdar, One way would be:
l <- list(a, b) do.call(cbind, lapply(l, function(x) x[1:max(sapply(l, length))])) HTH, Jorge On Sat, Nov 27, 2010 at 10:04 AM, Serdar Akin <> wrote: > Hi > > I'm trying two combine two vectors that have different lengths. This > without > recursive the shorter one. E.g., > > a <- seq(1:3) > b <- seq(1:6) > > Thanks in advance > > Serdar > > [[alternative HTML version deleted]] > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide > http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > [[alternative HTML version deleted]] ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
