Hi Harold, Thanks for your suggestion, which worked very well. I had to modify the pattern as I'm really dealing with larger grids than 10x10 so I needed a way to distinguish between for example position 1,11 and 11,1. The new function based on your suggestion runs in ~40% of the time compared with the original for loop construction, so it's an important saving! For the record, the new function is essentially as follows:
pixellate <- function(input, xPxNum = 128, yPxNum = 128, gain = 1){ temp <- matrix(data = 0, ncol = yPxNum, nrow = xPxNum) input <- subset(input, x <= xPxNum & x > 0 & y <= yPxNum & y > 0) #strip illegal pixel values input$patt <- input$x + (input$y - 1) * xPxNum #make unique identifier for each pixel counts <- as.data.frame(with(input, table(patt))) input <- merge(input, counts, by='patt') index <- matrix(c(input$x, input$y), ncol=2) #make an index matrix temp[index] <- input$Freq * gain temp } where input is a data frame consisting of x and y coordinates of events on a grid, 1 row per event, e.g. >input x y 1 86 63 2 75 16 3 122 34 4 8 17 5 1 7 6 115 81 7 103 125 8 76 54 9 114 117 10 96 18 ...and so on for many rows. Cheers David. -----Original Message----- From: Doran, Harold [mailto:[EMAIL PROTECTED] Sent: 06 February 2008 15:03 To: Doran, Harold; Waterman, DG (David); r-help@r-project.org Subject: RE: [R] counting row repetitions without loop Sorry, word wrap made that incomprehensible, I think x y 4 5 6 7 6 6 7 5 5 7 6 7 4 5 6 7 7 6 5 6 dat <- read.table('clipboard', header=TRUE) dat$patt <- paste(dat$x,dat$y, sep='') mm <- as.data.frame(with(dat, table(patt))) dat <- merge(dat, mm, by='patt') mat <- matrix(0, ncol=10, nrow=10) gg <- matrix(c(dat$x, dat$y), ncol=2) mat[gg] <- dat$Freq > -----Original Message----- > From: [EMAIL PROTECTED] > [mailto:[EMAIL PROTECTED] On Behalf Of Doran, Harold > Sent: Wednesday, February 06, 2008 9:56 AM > To: Waterman, DG (David); r-help@r-project.org > Subject: Re: [R] counting row repetitions without loop > > I think this does what you want, but there may be a more efficient way > > x y > 4 5 > 6 7 > 6 6 > 7 5 > 5 7 > 6 7 > 4 5 > 6 7 > 7 6 > 5 6 > dat <- read.table('clipboard', header=TRUE) # copy sample data above > dat$patt <- paste(dat$x,dat$y, sep='') mm <- as.data.frame(with(dat, > table(patt))) dat <- merge(dat, mm, > by='patt') mat <- matrix(0, ncol=10, nrow=10) gg <- matrix(c(dat$x, > dat$y), ncol=2) mat[gg] <- dat$Freq > > > -----Original Message----- > > From: [EMAIL PROTECTED] > > [mailto:[EMAIL PROTECTED] On Behalf Of Waterman, DG > > (David) > > Sent: Wednesday, February 06, 2008 9:08 AM > > To: r-help@r-project.org > > Subject: [R] counting row repetitions without loop > > > > Hi, > > > > I have a data frame consisting of coordinates on a 10*10 grid, i.e. > > > > > example > > x y > > 1 4 5 > > 2 6 7 > > 3 6 6 > > 4 7 5 > > 5 5 7 > > 6 6 7 > > 7 4 5 > > 8 6 7 > > 9 7 6 > > 10 5 6 > > > > What I would like to do is return an 10*10 matrix > consisting of counts > > at each position, so in the above example I would have a > matrix where, > > for example, cell [4,5] contains 2 and [6,7] contains 3. At > the moment > > I have implemented this using a for loop over the rows of the data > > frame, however the data frames I want to process are very > long so the > > loop takes many minutes to complete. Can I do this in a > more efficient > > way? > > > > Cheers, > > David > > <DIV><FONT size="1" color="gray">This e-mail and any > attachments may > > contain confidential, copyright and or privileged material, and are > > for the use of the intended addressee only. 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Registered in England and Wales with its registered office at Diamond House, Harwell Science and Innovation Campus, Didcot, Oxfordshire, OX11 0DE, United Kingdom </FONT></DIV> ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.