Does this version of y do what you want?
y=function(j)sum(sapply(1:3,function(i)x(i,j)))
- Phil Spector
Statistical Computing Facility
Department of Statistics
UC Berkeley
spec...@stat.berkeley.edu
On Sat, 13 Nov 2010, Hiba Baroud wrote:
Hi
I'm trying to sum functions of lists with different lengths. Here is a
simplified example of the problem:
r=list(1:3,1:5,1:2)
r
[[1]]
[1] 1 2 3
[[2]]
[1] 1 2 3 4 5
[[3]]
[1] 1 2
x=function(i,j) sum(j*r[[i]]) # x is a function of
two parameters: i & j
y=function(j) # y is the
sum of x over i
+ {
+ s=seq(from=1,to=3,by=1)
+ sum(x(s,j))
+ }
y(1)
Error in r[[i]] : recursive indexing failed at level 2
The error is clearly due to the lists; I actually tried this code with
functions of vectors and scalars and it worked perfectly.
I tried to use means of summing lists by recursion but it does not work with
functions of lists, for e.g.:
y=function(j) x(1,j)
for(i in 2:3)
+ {
+ y=function(j) y(j)+x(i,j)
+ }
y(1)
Error: evaluation nested too deeply: infinite recursion / options(expressions=)?
Is there a way to perform this summation?
Thanks!
H.
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