try this:
apply(data.matrix(a), 1, playFn)
I hope it helps.
Best,
Dimitris
On 11/9/2010 8:32 AM, Santosh Srinivas wrote:
Dear Group,
I have a following dataset:
a
A B C D
1 22 3 31 40
2 26 31 36 32
3 3 7 49 16
4 24 40 27 26
5 20 45 47 0
6 34 43 11 18
7 48 48 24 2
8 3 16 39 48
9 20 49 7 21
10 17 36 47 10
dput(a)
structure(list(A = c(22L, 26L, 3L, 24L, 20L, 34L, 48L, 3L, 20L,
17L), B = c(3L, 31L, 7L, 40L, 45L, 43L, 48L, 16L, 49L, 36L),
C = c(31L, 36L, 49L, 27L, 47L, 11L, 24L, 39L, 7L, 47L), D = c(40L,
32L, 16L, 26L, 0L, 18L, 2L, 48L, 21L, 10L)), .Names = c("A",
"B", "C", "D"), class = "data.frame", row.names = c(NA, -10L))
I have a function that works off EVERY individual ROW to throw a result.
Like
playFn<- function (x){
+ result = ((x$A+6*x$B)/(3*x$C)+20)*x$D
+ return(result)
+ }
I want to apply the function for every row .... can I use an "apply"
function ... tried but not been able to ...
e.g. print(rapply(a,playFn))
Please advise.
Thanks,
S
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--
Dimitris Rizopoulos
Assistant Professor
Department of Biostatistics
Erasmus University Medical Center
Address: PO Box 2040, 3000 CA Rotterdam, the Netherlands
Tel: +31/(0)10/7043478
Fax: +31/(0)10/7043014
Web: http://www.erasmusmc.nl/biostatistiek/
______________________________________________
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
