Hello again Jim (and everyone)
I am having a weird problem here with the same parsing thing.
For example, for the first row I have the following 5 columns.

1.0    2.0        3.8146973E-4        17    c(2,2)

I need to convert that c(2,2) into a list and get its mean, in this particular case mean=2. My program does:

t1 <- read.table(file="file.dat", header=T, colClasses=c("numeric", "numeric", "numeric", "numeric", "factor")) t1$lengthz <- lapply(t1$lengths, function(a) eval(parse(text=a)))#As Jim thought me t1$avglen <- as.vector(mode="numeric", lapply(t1$lengthz, function(i) mean(i)))

but the 6th column is strangely getting 780 instead of 2.
This solution used to work! :-(
Do you have any idea about what is going on?

I attach file.dat.

Thank you for your support.

Balpo


On 19/07/10 16:38, Balpo wrote:
 Thank you a lot, Jim.
Issue solved.

Balpo

On 16/07/10 11:27, jim holtman wrote:
Here is a way of creating a separate list of variable length vectors
that you can use in your processing:

# read into a dataframe
x<- read.table(textConnection("A    B    C    T    Lengths
+ 1    4.0    0.0015258789    18    c(1,2,3)
+ 1    4.0    0.0015258789    18    c(1,2,6,7,8,3)
+ 1    4.0    0.0015258789    18    c(1,2,3,1,2,3,4,5,6,7,9)
+ 1    4.0    0.0015258789    18    c(1,2,3)
+ 1    1.0    0.0017166138    24    c(1,1,4)"), header=TRUE)
# create a  'list' with the variable length vectors
# assuming the the "Lengths" are legal R expressions using 'c'
x$varList<- lapply(x$Lengths, function(a) eval(parse(text=a)))

x
A B C T Lengths varList 1 1 4 0.001525879 18 c(1,2,3) 1, 2, 3 2 1 4 0.001525879 18 c(1,2,6,7,8,3) 1, 2, 6, 7, 8, 3 3 1 4 0.001525879 18 c(1,2,3,1,2,3,4,5,6,7,9) 1, 2, 3, 1, 2, 3, 4, 5, 6, 7, 9 4 1 4 0.001525879 18 c(1,2,3) 1, 2, 3 5 1 1 0.001716614 24 c(1,1,4) 1, 1, 4
str(x)
'data.frame':   5 obs. of  6 variables:
  $ A      : int  1 1 1 1 1
  $ B      : num  4 4 4 4 1
  $ C      : num  0.00153 0.00153 0.00153 0.00153 0.00172
  $ T      : int  18 18 18 18 24
  $ Lengths: Factor w/ 4 levels "c(1,1,4)","c(1,2,3)",..: 2 4 3 2 1
  $ varList:List of 5
   ..$ : num  1 2 3
   ..$ : num  1 2 6 7 8 3
   ..$ : num  1 2 3 1 2 3 4 5 6 7 ...
   ..$ : num  1 2 3
   ..$ : num  1 1 4
On Fri, Jul 16, 2010 at 10:51 AM, Balpo<ba...@gmx.net>  wrote:
  Hello to all!
I am new with R and I need your help.
I'm trying to read a file which contests are similar to this:
A    B    C    T    Lengths
1    4.0    0.0015258789    18    c(1,2,3)
1    1.0    0.0017166138    24    c(1,1,4)

So all the columns are numeric values, except Lengths, which is supposed to
be an variable length array of integers.
How can I make R read them as arrays of integers? Or otherwise, convert the
character array to an array of integers.
When I read the file, I do it like this
t1 = read.table(file=paste("./borrar.dat",sep=""), header=T,
colClasses=c("numeric", "numeric", "numeric", "numeric", "array"))
But the 5th column is treated as an array of characters, and when trying to
convert it to another class of data, I either
get two strings "c(1,2,3)" and "c(1,1,4)" or using a toRaw converter, I get
the corresponding ASCII ¿? values.
Should the input be modified in order to be able to read it as an array of
integers?

Thank you for your help.
Balpo

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______________________________________________
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and provide commented, minimal, self-contained, reproducible code.

ktot    attractors      pctstatesinattractors   t       lengths
1.0     2.0             3.8146973E-4            17      c(2,2)
1.0     1.0             5.722046E-4             28      c(2)
1.0     2.0             9.536743E-4             18      c(2,2)
1.0     1.0             0.0010490417            14      c(1)
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.

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