How about:
sum(unlist(strsplit(b,NULL))==";")
# [1] 5
(More transparent, at least to me ... ). See '?strsplit',
and note what is said under "Value".
Ted.
On 11-Oct-10 04:35:43, Michael Sumner wrote:
> Literally:
>
> length( gregexpr(";", b)[[1]])
>
> But more generally, in case b has more than one element:
>
> sapply(gregexpr(";", b), length)
>
> ?gregexpr
>
>
>
> On Mon, Oct 11, 2010 at 3:18 PM, Santosh Srinivas <
> santosh.srini...@gmail.com> wrote:
>
>> New to R ... which is a function to most effectively search the number
>> of
>> occurrences of a character in a string?
>>
>> b <-
>> c("jkhrikujhj345hi5hiklfjsdkljfksdio324j';;'lfd;g'lkfit34'5;435l;43'5k"
>> )
>>
>> I want the number of semi-colons ";" in b?
>> Thanks.
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E-Mail: (Ted Harding) <ted.hard...@wlandres.net>
Fax-to-email: +44 (0)870 094 0861
Date: 11-Oct-10 Time: 09:20:36
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