On Oct 5, 2010, at 11:17 PM, Carrie Li wrote:

Thank you, Henrik! That makes more sense now.
You mentioned that every double value needs 8 bytes. So, in R, how many decimal point, or any number smaller than, say 10^4 are considered as double value ? (Sorry I don't have any C or Java language background, and couldn't
find it for R. )

You can specify an integer mode for a vector by using an "L" after the digits used in its definition or by using mode = integer in the call to the vector function. You can test for integer statsus with is.integer and coerce to integer status with as.integer. IN all other instances you should assume that the storage mode is double. The storage mode does not vary by element, and an integer vector can quickly be coerced to double if you make an assignment of double mode.

> a <- c(1L, 2L, 3L)
> a
[1] 1 2 3
> is.integer(a)
[1] TRUE
> a[3] <- 1.2
> is.integer(a)
[1] FALSE


After coercion to double the vector will now take up the full 8 bytes (plus overhead) per element, but is rather set at the vector level:

> b <- rep(1L, 100)
> object.size(b)
440 bytes
> b[100] <- 1.2    # change single element to double.
> object.size(b)
840 bytes

--
David.




I appreciate your explanation and helps!

On Tue, Oct 5, 2010 at 8:32 PM, Henrik Bengtsson <h...@stat.berkeley.edu>wrote:

On Tue, Oct 5, 2010 at 5:21 PM, Carrie Li <carrieands...@gmail.com> wrote:
I am sorry that it has been couple days.
I've read the website you provided below, but still don't quite know if
this
is doable.
The maximum vector length is 2^31-1, so here is what I tired, and it
returned errors as below.


P=20000
D=matrix(rep(0, P*P), nrow=P)

Error: cannot allocate vector of size 1.5 Gb
In addition: Warning messages:
1: In as.vector(data) :
Reached total allocation of 1535Mb: see help(memory.size)

On the manuals, it says "32-bit OSes by default limit file sizes to 2GB
",
so why P=20000 is not working here ?

Every double value (e.g. 0) needs 8 bytes. So the total memory needed for that matrix is 8*P*P = 3.2e+09 bytes = 3.2e+09/1024^3 Gb = 2.98Gb.
Now, in order to do anything useful you also need space for creating
an internal copy or two of that object.  That is, you basically need
2-3 times more *free* (and *contiguous/non-fragmented*) RAM than that
to do anything useful.

/Henrik


Thanks for any helps. I appreciate.


On Sat, Oct 2, 2010 at 12:22 PM, Marc Schwartz <marc_schwa...@me.com>
wrote:

On Oct 2, 2010, at 11:14 AM, Carrie Li wrote:

Hi everyone,

If I run on a 64-bit R, what is the maximum matrix size that it can
handle ?
Is a matrix 20,000 x 20,000 possible on 32 bit ?
Thanks for answering!


A matrix is a vector with 'dim' attributes. The maximum vector length is 2^31 - 1 and that does not change between 32 and 64 bit R. The primary
advantage of 64 bit R is the larger memory address space.

See:



http://cran.r-project.org/doc/manuals/R-admin.html#Choosing-between-32_002d-and-64_002dbit-builds

HTH,

Marc Schwartz



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