Dear Jamesp,
This might be (more?) fitting for a blog then the R-help mailing list.

I'd suggest you to open a blog on (it takes less then 4 minutes):
wordpress.com
It now has syntax highlighting for R code:
http://www.r-statistics.com/2010/09/r-syntax-highlighting-for-bloggers-on-wordpress-com/
I also combined a list of tips for the R blogger <http://r-bloggers.com/>,
on this post:
http://www.r-statistics.com/2010/07/blogging-about-r-presentation-and-audio/


Cheers,
Tal


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On Sat, Oct 2, 2010 at 11:27 PM, Jamesp <james.jrp...@gmail.com> wrote:

>
> I just started using R and I'm having all sorts of "fun" trying different
> things.
>
> I'm going to document the different things I'm doing here as a kind of case
> study.  I'm hoping that I'll get help from the community so that I can use
> R
> properly.
>
> Anyways, in this study, I have demographic data, drug usage data, and side
> effect data.  All of this is loaded into a csv file.  I'm using Rweb as an
> interface, so I had to modify the cgi-bin code slightly, but it works
> pretty
> well.  I'm looking for frequency counts, some summary data for columns
> where
> it makes sense, plots and X-squared tests.  My data frame is named X since
> that's what Rweb names it.
>
>
> ----------------------------------------------------------------------------------------------------
> 1) I was thinking I'd have to go through each nominal variable (i.e.
> table(X$race) ), but I think I have it figured out now.  summary(X) is
> nice,
> but I need to recode nominal data with labels so the results are
> meaningful.
>
>
> -----------------------------------------------------------------------------------------------------
> 2) I had an issue with multiple plots overwriting each other, and I managed
> to bypass that with:
> par(mfrow=c(2,1))
> I have to update it to correspond to the number of plots I think.  There's
> probably a better way to do this.
>
> barplot(table(X$race))  prints out a barplot so that's great
>
>
> -----------------------------------------------------------------------------------------------------
> 3) I was able to code my data so it shows up in tables better with
> X$race <- factor(X$race, levels = c(0,2), labels = c("African
> American","White,Non-Hispanic"))
>
>
> ----------------------------------------------------------------------------------------------------
>
> !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
>
> ----------------------------------------------------------------------------------------------------
> 4) The coding for all of my drug variables is identical, and I'd like to
> create a loop that goes through and labels accordingly
>
> I'm not having good success with this yet, but here's what I'm trying.
>
> X[1,] <- factor(X[1,], levels = c(0,1,2,3,4,5), labels= c("none","last
> week","last 3 month","last year","regular use at least 3 months","unknown
> length of usage"))
>
> I know I would need to replace the [1,] with something that gives me the
> column, but I'm not sure what to put syntactically at the moment.
>
>
> ----------------------------------------------------------------------------------------------------
> 5) I had more success creating new variables based on the old ones.  So I
> end up with yes/no answers to drug usage
>
> for (i in 24:56)
> {
>  X[,i+173] <- ifelse(X[,i] >0,c(1),c(0))
> }
>
> I'd like to have been able to make a new variable name based off of the old
> variable name (i.e. dropping "_when" from the end of each and replace it
> with "_yn")
>
>
> ---------------------------------------------------------------------------------------------------
>
> !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
>
> ---------------------------------------------------------------------------------------------------
> 6)  I'm able to make a cross-tabulated table and perform a X-squared test
> just fine with my recoded variable
>
> table(X$race,X[,197])
> prop.test(table(X$race,X[,197]))
>
> but I would like to be able to do so with all of my drugs, although I can't
> seem to make that work
>
> for (i in 197:229)
> {
>  table(X$race,X[,i])
>  prop.test(table(X$race,X[,i]))
> }
>
>
> -------------------------------------------------------------------------------------------------
>
> Thanks for reading over this and I do appreciate any help.  I understand
> that there's "an R way" of doing things, and I look forward to learning the
> method.
> --
> View this message in context:
> http://r.789695.n4.nabble.com/Non-Parametric-Adventures-in-R-tp2952754p2952754.html
> Sent from the R help mailing list archive at Nabble.com.
>
> ______________________________________________
> R-help@r-project.org mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide
> http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>

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