Hi Wesley, Try this (untested):
s <- array(0, dim = c(2, 2, 4)) for(i in 1:4) s[, ,i] <- read_matrix(a, 2, 2) Another (untested) option wold be s0 <- lapply(1:4, function(i) read_matrix(a, 2, 2)) s0 HTH, Jorge On Mon, Sep 27, 2010 at 6:12 AM, wesley mathew <> wrote: > Dear All > > I want to store matrix in an array > Suppose s<-array(0,4) > for(i in 1:4) > s[i] <- read_matrix(a,2,2) > But the error - number of items to replace is not a multiple of replacement > length. > Can you suggest me any alternative method for storing a matrix in an array. > Thanks In advance. > Kind Regards > Wesley C Mathew > > [[alternative HTML version deleted]] > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide > http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > [[alternative HTML version deleted]] ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
